document.write( "Question 258832: A certain airplane has two independent alternators to provide electrical power. The probability that a given alternator will fail on a one-hour flight is .02. What is the probability that (a) both will fail? (b) Neither will fail? (c) One or the other will fail? Show all steps carefully.\r
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Algebra.Com's Answer #190595 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Fombitz did some good calculating but read the data incorrectly.
\n" ); document.write( "It is .02 not .2
\n" ); document.write( "P(both fail)=\"%280.2%29%280.2%29=0.04\"
\n" ); document.write( "P(neither fail)=\"%280.8%29%280.8%29=0.64\"
\n" ); document.write( "P(one fails)=P(first fails,second doesn't)+P(first doesn't, second fails)=\"%280.2%29%280.8%29%2B%280.8%29%280.2%29=0.32\"
\n" ); document.write( "Ptotal=\"0.04%2B0.64%2B0.32=1\" (all possible events are covered\r
\n" ); document.write( "\n" ); document.write( "Adjusting the work then
\n" ); document.write( "P(both fail)=\"%280.02%29%280.02%29=0.0004\" 2/100*2/100=4/10000
\n" ); document.write( "P(neither fail)=\"%280.98%29%280.98%29=0.9604\"
\n" ); document.write( "P(one fails)=P(first fails,second doesn't)+P(first doesn't, second fails)=\"%280.02%29%280.98%29%2B%280.98%29%280.02%29=0.0392\"\r
\n" ); document.write( "\n" ); document.write( "If the first doesn't fail how are you going to know if the second one did failed?
\n" ); document.write( "Ptotal=\"0.0004%2B0.9604%2B0.0392=1\" (all possible events are covered
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