document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258810>Question 258810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photographer is mixing 5% acetic acid solution with a 10% acetic acid solution to get 2 liters of a 7% solution. How many liters of each solution should he add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190528 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A photographer is mixing 5% acetic acid solution with a 10% acetic acid solution to get 2 liters of a 7% solution. How many liters of each solution should he add?\r<BR>\n" );
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document.write( "5% solution X, 10% solution Y<BR>\n" );
document.write( "X+Y=2  --> X=2-Y<BR>\n" );
document.write( "0.07*2 liters = 0.14 liters acetic acid\r<BR>\n" );
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document.write( "0.05(2-Y) + 0.10Y = 0.14<BR>\n" );
document.write( "0.10 - 0.05Y + 0.10Y = 0.14<BR>\n" );
document.write( "0.10 + 0.05Y = 0.14<BR>\n" );
document.write( "0.05Y = 0.04<BR>\n" );
document.write( "Y=0.04/0.05=4/5=0.8 liters of 10% ascetic acid solution<BR>\n" );
document.write( "and since X+Y=2\r<BR>\n" );
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document.write( "we will need 1.2 liters of the 5% and 0.8 liters of the 10%\r<BR>\n" );
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