document.write( "Question 258790: This is actually solving a problem that is quadratic in form. I am having lots of difficulties trying to figure this one out trying to substitute, but even sure if that is what I am supposed to do and totally stumped. Here is the problem:\r
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document.write( "(x-3)^2/5=(4x)^1/5\r
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document.write( "If I let u = (x-3)^1/3, it still doesn't quite make it into a quadratic as it then looks like:
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document.write( "u^2=(4x)^1/5\r
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document.write( "This is where I am stumped, not sure how to proceed after this since I can't use u to equal the 4x also as they are not like terms.\r
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document.write( "(and the exponents are fractions) \n" );
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Algebra.Com's Answer #190516 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Solve for x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Caution! Check the solutions by substituting into the given equation to discover any possible \"extraneous\" solutions.. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Both solutions are valid! \n" ); document.write( " |