document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258794>Question 258794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the system of linear equations:<BR>\n" );
document.write( "4x + 10y = -28<BR>\n" );
document.write( "6x + 7y = 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190511 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's multiply the first equation by 6 and the second one by -4. That will give us:<BR>\n" );
document.write( "24x + 60y = -168<BR>\n" );
document.write( "-24x -28y = -24<BR>\n" );
document.write( "Now we can add both of these together and gives us:<BR>\n" );
document.write( "32y=-192 Divide both sides by 32  will be:<BR>\n" );
document.write( "y=-6 Now we can plug this into either original equation:<BR>\n" );
document.write( "4x + 10(-6) = -28 Add 60 to both sides will be:<BR>\n" );
document.write( "4x=32 Divide both sides by 4 to be:<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "Now plug both answers x=8 and y=-6 into both equations to see if it works out. <BR>\n" );
document.write( "RJ <BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );