document.write( "Question 258797: Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of the year is $3,390, how much did she invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #190510 by stanbon(75887) ![]() You can put this solution on YOUR website! Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of the year is $3,390, how much did she invest at 15%? \n" ); document.write( "--------------------- \n" ); document.write( "Using two variables: \n" ); document.write( "Equations: \n" ); document.write( "Quantity Equation: x + y = 27000 \n" ); document.write( "Interest Equation:0.15x + 0.09y = 3390 \n" ); document.write( "---------------------------------------- \n" ); document.write( "Multiply thru the 1st equation by 9 \n" ); document.write( "Multiply thru the 2nd equation by 100 \n" ); document.write( "----- \n" ); document.write( "9x + 9y = 9*27000 \n" ); document.write( "15x+ 9y = 339000 \n" ); document.write( "------------------------ \n" ); document.write( "Subtract the 1st from the 2nd and solve for \"x\": \n" ); document.write( "6x = 96000 \n" ); document.write( "x = $16,000 (amt. invested at 15 % \n" ); document.write( "------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |