document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258779>Question 258779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this problem by using a two order system.\r<BR>\n" );
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document.write( "John is 5 years older than Mary. In 10 years, twice John's age decreased by Mary's age is 35, and John's age will be twice Mary's current age. Find their ages now.\r<BR>\n" );
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document.write( "John is  years old ?, and Mary is ? years old.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190494 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Again no idea what you mean by \"two order system\"<BR>\n" );
document.write( "j=m+5 and <BR>\n" );
document.write( "2(j+10)-(m+10)=35 and <BR>\n" );
document.write( "j+10=2m<BR>\n" );
document.write( "j=20<BR>\n" );
document.write( "m=15\r<BR>\n" );
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document.write( "We can solve by just using the first and last equations.<BR>\n" );
document.write( "j=m+5<BR>\n" );
document.write( "j+10=2m<BR>\n" );
document.write( "m+5+10=2m<BR>\n" );
document.write( "m+15=2m<BR>\n" );
document.write( "15=m<BR>\n" );
document.write( "j=20<BR>\n" );
document.write( "Just for fun lets check using the unused equation<BR>\n" );
document.write( "2(j+10)-(m+10)=35 <BR>\n" );
document.write( "2(30)-25=35<BR>\n" );
document.write( "60-25=35<BR>\n" );
document.write( "35=35<BR>\n" );
document.write( "ok </SPAN>\n" );
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