document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258765>Question 258765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the first n terms in a sequence is always 1/n. Find the product of the first 2007 terms.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190477 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the first n terms in a sequence is always 1/n. Find the product of the first 2007 terms. <BR>\n" );
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document.write( "2007/n is the number of times you have n terms in 2007<BR>\n" );
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document.write( "Each of those n terms sets adds up to 1/n<BR>\n" );
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document.write( "So the sum is (2007/n)(1/n) = 2007/n^2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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