document.write( "Question 32494This question is from textbook
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document.write( ": i am stuck on the parabolas and i just can't seem to figure it out. Here is one of the problems i am working on. x=y2 + 14y + 20. (the 2 next to the y is y squared)well i get stuck on this part x= (y2 + 14y + _____)+20 ______ i just cant figure out how to find the numbers that go in those places. please help me \n" );
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Algebra.Com's Answer #19047 by mukhopadhyay(490)![]() ![]() ![]() You can put this solution on YOUR website! x=y^2 + 14y + 20 \n" ); document.write( "This is a parabola having directrix parallel to the y-axis (sidewise, opening on the right side). \n" ); document.write( "x = y^2+14y+20 \n" ); document.write( "=> x = y^2 + 14y + 49 - 29 \n" ); document.write( "=> x = (y+7)^2 - 29 \n" ); document.write( "The vertex of the parabola is at (-29, -7). \n" ); document.write( "The directrix of the parabola is at y = -14 \n" ); document.write( "Let me know if you need any additional information. \n" ); document.write( " |