document.write( "Question 258695: I am unsure if I am submitted this question to right area but here goes. Ot os listed as Aplications: Mixture and Unform Motion Problems. \r
\n" ); document.write( "\n" ); document.write( "A student rode a bycycle to the repair shop then walked home. The student averaged 14mph ridign to the shop and 3.5mph walking home. The route took 1 hour. How far is it from the student's home to the repair shop. I am unsure how to even set up the equation. All I do know is he rides 4x as fast as he walks.
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Algebra.Com's Answer #190448 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
\n" ); document.write( "The distance is the same going to and coming from the shop.
\n" ); document.write( "It takes t1 hrs to get to the shop by bike and it takes t2 hrs to get to the shop on foot.
\n" ); document.write( "\"t1%2Bt2=1\"
\n" ); document.write( "\"R1%2At1=d\"
\n" ); document.write( "\"14t1=d\"
\n" ); document.write( "\"R2%2At2=d\"
\n" ); document.write( "\"3.5t2=d\"
\n" ); document.write( "Since they both equal d, they equal each other.
\n" ); document.write( "1.\"14t1=3.5t2\"
\n" ); document.write( "2. \"t1%2Bt2=1\"
\n" ); document.write( "Now you have 2 equations with 2 unknowns.
\n" ); document.write( "Please re-post if you need more help.
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