document.write( "Question 32568: The population of deer living in an enclosed game reserve displays regular fluctuations in size. Wildlife biologists have chosen to model the population size with a sinusoidal function. At its height the deer population is 7000, while at its low it is 2000. The time between highs and lows is 6 months. The population at the start of January, 2001 is 4500 and decreasing. Consider January, 2001 to correspond to time t = 0.\r
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document.write( "a) Model the deer population as a function of time t in months. \r
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document.write( "I'm just having a little trouble with the actual function for this one, I managed to figure out the graph I think but can't figure out how to set up the function with the numbers given. Please help if you can...\r
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document.write( "Thanks a bunch, you guys are always such a big help. \n" );
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Algebra.Com's Answer #19037 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Equation you want is y=Asin(BX+C)+D \n" ); document.write( "amplitude = A = (7000-2000)/2=2500 \n" ); document.write( "period = 6 mths = (2pi/B); so B=pi/6 \n" ); document.write( "Shift = -C/B=-C/[pi/6]; shift is 6 mths to the left; \n" ); document.write( "So -C/[pi/6]=+6 and C=-pi \n" ); document.write( "Translation is +4500; so D=4500 \n" ); document.write( "Equation is y=2500sin[(pi/6)t-pi]+4500 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |