document.write( "Question 258526: jim and sue have 72 coins that are nickels and dimes. The value of the coins is 5.80. How many of each do they have? \n" ); document.write( "
Algebra.Com's Answer #190340 by checkley77(12844)\"\" \"About 
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N+D=72 OR N=72-D
\n" ); document.write( ".05(72-D)+.10D=5.80
\n" ); document.write( "3.6-.05D+.10D=5.80
\n" ); document.write( ".05D=5.80-3.60
\n" ); document.write( ".05D=2.20
\n" ); document.write( "D=2.20/.05
\n" ); document.write( "D=44 NUMBER OF DIMES.
\n" ); document.write( "N=72-44
\n" ); document.write( "N=28 NUMBER OF NICKELS.
\n" ); document.write( "PROOF:
\n" ); document.write( ".05*28+.10*44=5.80
\n" ); document.write( "1.40+4.40=5.80
\n" ); document.write( "5.80=5.80
\n" ); document.write( "
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