document.write( "Question 258526: jim and sue have 72 coins that are nickels and dimes. The value of the coins is 5.80. How many of each do they have? \n" ); document.write( "
Algebra.Com's Answer #190340 by checkley77(12844) ![]() You can put this solution on YOUR website! N+D=72 OR N=72-D \n" ); document.write( ".05(72-D)+.10D=5.80 \n" ); document.write( "3.6-.05D+.10D=5.80 \n" ); document.write( ".05D=5.80-3.60 \n" ); document.write( ".05D=2.20 \n" ); document.write( "D=2.20/.05 \n" ); document.write( "D=44 NUMBER OF DIMES. \n" ); document.write( "N=72-44 \n" ); document.write( "N=28 NUMBER OF NICKELS. \n" ); document.write( "PROOF: \n" ); document.write( ".05*28+.10*44=5.80 \n" ); document.write( "1.40+4.40=5.80 \n" ); document.write( "5.80=5.80 \n" ); document.write( " |