document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258388>Question 258388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side of a triangle is 18 feet longer that its shortest side. The remaining side is 11 feet less than 3 times the length of the shortest side. Find The dimensions of the triangle if the perimeter of it is 137 feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190323 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=S+18<BR>\n" );
document.write( "Y=3S-11<BR>\n" );
document.write( "X+Y+S=137<BR>\n" );
document.write( "S+18+3S-11+S=137<BR>\n" );
document.write( "5S=137-18+11<BR>\n" );
document.write( "5S=130<BR>\n" );
document.write( "S=130/5<BR>\n" );
document.write( "S=26 FT. FOR THE SHORTEST SIDE.<BR>\n" );
document.write( "X=26+18=44 FT. FOR THE MIDDLE SIDE.<BR>\n" );
document.write( "Y=3*26-11=78-11=67 FT. FOR THE LONGER SIDE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "26+44+67=137<BR>\n" );
document.write( "137=137 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );