document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32488>Question 32488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the domain of -(square root of x+9)+3.  I have graphed out the problem and my thought was x/x is greater than or equal to -9. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19032 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Domain of -(sqr(x+9)+3 can be found from the restriction below:<BR>\n" );
document.write( "square root of (x+9) produces a real number as long as x+9 >= 0<BR>\n" );
document.write( "Domain is: x >= -9<BR>\n" );
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