document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258515>Question 258515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 3 less than another.  their sum is 15. find the numbers.  this is a word problem i got x-3x=15 but it does not come out to the answers.  the answers are 9,6.  i have no idea how to set it up> </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190318 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X = first number and Y = second number<BR>\n" );
document.write( "\"one number is 3 less than another\" translates to<BR>\n" );
document.write( "(i) X = Y  - 3<BR>\n" );
document.write( "\"their sum is 15\" translates to<BR>\n" );
document.write( "(ii) X + Y = 15<BR>\n" );
document.write( "solve by substitution to get<BR>\n" );
document.write( "(iii) Y - 3 + Y = 15<BR>\n" );
document.write( "solving for Y we get<BR>\n" );
document.write( "2Y - 3 = 15<BR>\n" );
document.write( "2Y = 18<BR>\n" );
document.write( "Y = 9<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "X = 6<BR>\n" );
document.write( "We have (X,Y) = (6,9) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );