document.write( "Question 258432: An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its trip, with the wind, it takes only 5 hours. Find the rate of the airplane with no wind. Find the rate of the wind \n" ); document.write( "
Algebra.Com's Answer #190258 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! rt=d \n" ); document.write( "r*6=900=3*300=3*2*150=150\r \n" ); document.write( "\n" ); document.write( "s*5=900=6*150=6*30*5=180 \n" ); document.write( "180-150=30 \n" ); document.write( "30/2=15 mph wind \n" ); document.write( "airplane 165 mph with no wind. \n" ); document.write( " \n" ); document.write( " |