document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258389>Question 258389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the shortest distance from (9,5) to 5x + 3y =15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190225 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I had to think a second about this one. <BR>\n" );
document.write( "They are asking for the equation that for the line which passes through (9,5) and is  perpendicular to 5x + 3y =15.<BR>\n" );
document.write( "Then we need the intersection of the two lines and then the distance from the intersection to (9,5)\r<BR>\n" );
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document.write( "so find the slope of 5x + 3y =15<BR>\n" );
document.write( "3y=15-5x<BR>\n" );
document.write( "y=15/3-5x/3<BR>\n" );
document.write( "m=-5/3<BR>\n" );
document.write( "perpendicular slope would be 3/5<BR>\n" );
document.write( "5=3/5(9)+b<BR>\n" );
document.write( "25=27+5b<BR>\n" );
document.write( "-2=5b<BR>\n" );
document.write( "-2/5=b<BR>\n" );
document.write( "y=3/5x-2/5<BR>\n" );
document.write( "5x + 3y =15<BR>\n" );
document.write( "5y=3x-2 and <BR>\n" );
document.write( "3x-2=5y\r<BR>\n" );
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document.write( "3x-5y=2<BR>\n" );
document.write( "5x+3y=15<BR>\n" );
document.write( "9x-15y=6<BR>\n" );
document.write( "25x+15y=75<BR>\n" );
document.write( "34x=81\r<BR>\n" );
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document.write( "x = 81/34,   y = 35/34<BR>\n" );
document.write( "(9,5)<BR>\n" );
document.write( "(81/34,35/34)<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "sqrt((9-81/34)^2 +(5-35/34)^2)=<BR>\n" );
document.write( "7.7 units\r<BR>\n" );
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document.write( "Here are some other ways to do it. Some much shorter.<BR>\n" );
document.write( "http://www.worsleyschool.net/science/files/linepoint/distance.html </SPAN>\n" );
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