document.write( "Question 258380: On the first day, Joe joined a secret club as its only member. Each day after that, one more member joined than on the previous day. What was the membership of the club after 40 days?\r
\n" ); document.write( "\n" ); document.write( "((( I did this: 40 multiplied by 2 ; because it says each day after one more member joined than on the previous. So then I got 80 and added joe and got 81???)))
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Algebra.Com's Answer #190218 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
day joined membership
\n" ); document.write( "0 0 0
\n" ); document.write( "1 1 1
\n" ); document.write( "2 2 3
\n" ); document.write( "3 3 6
\n" ); document.write( "4 4 10
\n" ); document.write( "5 5 15
\n" ); document.write( "6 6 21
\n" ); document.write( "7 7 28
\n" ); document.write( "8 8 36
\n" ); document.write( "9 9 45
\n" ); document.write( "10 10 55
\n" ); document.write( "11 11 66
\n" ); document.write( "12 12 78
\n" ); document.write( "13 13 91\r
\n" ); document.write( "\n" ); document.write( "The new total is the previous total plus the new day
\n" ); document.write( "#8 is 36 which is 1/2*8*9
\n" ); document.write( "#10 is 55 which is 1/2*10*11=55
\n" ); document.write( "#12 78 1/2 12*13=6*13
\n" ); document.write( "total = day*day+1*1/2
\n" ); document.write( "It also works with odd numbers
\n" ); document.write( "#11 11*12*1/2=66
\n" ); document.write( "so we have
\n" ); document.write( "t=d*(d+1)*1/2
\n" ); document.write( "t=40*41*1/2
\n" ); document.write( "t=20*41=820 after 40 days
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