document.write( "Question 258241: a 16 inch wire cut into two pieces bent into squares find the length if the sum of the areas is 10 in squared \n" ); document.write( "
Algebra.Com's Answer #190199 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let x = side of one square
\n" ); document.write( "Let y = side of the other square
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\n" ); document.write( "Write an equation for each phrase
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\n" ); document.write( "a 16 inch wire cut into two pieces bent into squares
\n" ); document.write( "4x + 4y = 16
\n" ); document.write( "simplify, divide by 4
\n" ); document.write( "x + y = 4
\n" ); document.write( "x = (4-y)
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\n" ); document.write( "find the length if the sum of the areas is 10 in squared
\n" ); document.write( "x^2 + y^2 = 10
\n" ); document.write( "Replace x with (4-y)
\n" ); document.write( "(4-y)^2 + y^2 = 10
\n" ); document.write( "FOIL
\n" ); document.write( "16 - 8y + y^2 + y^2 = 10
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "2y^2 - 8y + 16 - 10 = 0
\n" ); document.write( "2y^2 - 8y - 6 = 0
\n" ); document.write( "Simplify divide by 2
\n" ); document.write( "y^2 - 4y + 3 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(y - 1)(y - 3) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "y = 1, then x = 3
\n" ); document.write( "y = 3, then x = 1
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\n" ); document.write( "Check:
\n" ); document.write( " 4(1) + 4(3) = 16
\n" ); document.write( "3^2 + 1^2 = 10\r
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