document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258311>Question 258311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let's see if you guys can bail me out again tonight with another story problem.  I actually have it solved (FINALLY), but will post my question at the end.  The problem:\r<BR>\n" );
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document.write( "Movie tickets cost $25 for adults, and $5.00 for children.  Last night a total of 305 tickets were sold totalling $6025,  How many of each ticket was sold?\r<BR>\n" );
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document.write( "I was able to set up the first part of the equation with no problem, but I kept wanting the right side to be 305 instead of 6025.\r<BR>\n" );
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document.write( "It took me an hour to realize it should read:\r<BR>\n" );
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document.write( "c(5) + (305 - c)(25) = 6025<BR>\n" );
document.write( "and NOT  c(5) + (305 - c)(25) = 225\r<BR>\n" );
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document.write( "That just makes so much more sense to me.  Am I not looking for the number of tickets?\r<BR>\n" );
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document.write( "Ive ran into this same problem numerous times.  I can get the first part of the equation set up, then flounder helplessly with the back 1/2.  In some problems both numbers are required ( as in 6025(305) ) and sometimes it's just one of the numbers...but I'm having a hard time figuring out which one!  This is probably one of those deals where you either see it or you don't, but I hoped maybe someone would have some kind of pointer for me.\r<BR>\n" );
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document.write( "Thanks a million in advance!<BR>\n" );
document.write( "La\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190152 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190152\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Movie tickets cost $25 for adults, and $5.00 for children. Last night a total of 305 tickets were sold totalling $6025, How many of each ticket was sold? \r<BR>\n" );
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document.write( "let a = number of adult tickets sold.<BR>\n" );
document.write( "let c = number of child tickets sold.\r<BR>\n" );
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document.write( "25 * a + 5 * c = 6025\r<BR>\n" );
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document.write( "a + c = 305\r<BR>\n" );
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document.write( "you have 2 equations that have to be solved simultaneously (same solution for both equations).\r<BR>\n" );
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document.write( "solve for a or c in the second equation and then use that to solve for the remaining variable in the first equation.\r<BR>\n" );
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document.write( "a + c = 305\r<BR>\n" );
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document.write( "solve for a to get:\r<BR>\n" );
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document.write( "a = 305 - c\r<BR>\n" );
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document.write( "substitute for a in the first equation.\r<BR>\n" );
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document.write( "first equation is:\r<BR>\n" );
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document.write( "25 * a + 5 * c = 6025\r<BR>\n" );
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document.write( "substitute 305 - c for a to get:\r<BR>\n" );
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document.write( "25 * (305 - c) + 5 * c = 6025\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "7625 - 20*c = 6025\r<BR>\n" );
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document.write( "subtract 7625 from both sides of the equation to get:\r<BR>\n" );
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document.write( "-20*c = 6025 - 7625 = -1600\r<BR>\n" );
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document.write( "divide both sides of the equation by -20 to get:\r<BR>\n" );
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document.write( "c = -1600/-20 = 80\r<BR>\n" );
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document.write( "since a + c = 305, then a must be equal to 305 - 80 = 225\r<BR>\n" );
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document.write( "225 + 80 = 305\r<BR>\n" );
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document.write( "25 * 225 + 80 * 5 = 5625 + 400 = 6025\r<BR>\n" );
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document.write( "numbers look good.\r<BR>\n" );
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document.write( "answer is:\r<BR>\n" );
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document.write( "number of adult tickets is 225<BR>\n" );
document.write( "number of child tickets is 80\r<BR>\n" );
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document.write( "the number of tickets sold is a + c = 305\r<BR>\n" );
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document.write( "the amount of money made is 25*a + 5*c = 6025\r<BR>\n" );
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document.write( " </SPAN>\n" );
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