document.write( "Question 258252: I am trying to find the measure for the angles of a triangle. One angle is twice the measure of a 2nd angle, & the 3rd angle is three times the 2nd angle decreased by 12. The answer is in the back of the book. But I want to know how to get there from here. \n" ); document.write( "
Algebra.Com's Answer #190111 by ankor@dixie-net.com(22740)\"\" \"About 
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One angle is twice the measure of a 2nd angle, & the 3rd angle is three times the 2nd angle decreased by 12.
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\n" ); document.write( "Reading it we can see it would be good to get the 1st and 3rd angles in terms of the 2nd angle
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\n" ); document.write( "Let x = the 2nd angle
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\n" ); document.write( "It says,\"One angle is twice the measure of a 2nd angle\", therefore
\n" ); document.write( "\"one angle\" = 2x
\n" ); document.write( "and
\n" ); document.write( "\"the 3rd angle is three times the 2nd angle decreased by 12.\", therefore:
\n" ); document.write( "3rd angle = 3x - 12
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\n" ); document.write( "It's a triangle so we can say:
\n" ); document.write( "2x + x + (3x-12) = 180
\n" ); document.write( "6x = 180 + 12
\n" ); document.write( "6x = 192
\n" ); document.write( "x = \"192%2F6\"
\n" ); document.write( "x = 32 degrees is the 2nd angle
\n" ); document.write( "then
\n" ); document.write( "2(32) = 64 degrees is the one angle
\n" ); document.write( "and
\n" ); document.write( "3(32) - 12 = 84 degrees is the 3rd angle
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\n" ); document.write( ":
\n" ); document.write( "confirm this: 64 + 32 = 84 = 180
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\n" ); document.write( "did this light way for you on this problem? \n" ); document.write( "
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