document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258234>Question 258234</A>: <I><SPAN STYLE=\"word-break: break-all;\">  How do I solve this problem f(x) = -0.3x^2 + 25x + 16 using the quadratic formula and graphing...I'm lost. I know  x = 1 if this helps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190083 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How do I solve this problem f(x) = -0.3x^2 + 25x + 16 using the quadratic formula and graphing<BR>\n" );
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document.write( "You use the quadratic formula to find roots or zeroes of the equation.<BR>\n" );
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document.write( "-0.3x^2 + 25x + 16 = 0<BR>\n" );
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document.write( "x = [-25 +- sqrt(25^2 - 4*-0.3*16)]/(2*-0.3)<BR>\n" );
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document.write( "x = [-25 +- sqrt(625 + 19.2)]/(-0.6)<BR>\n" );
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document.write( "x = [-25 + 25.3811]/(-0.6) or x = [-50.3811]/(-0.6) = 83.97<BR>\n" );
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document.write( "x = 0.3811/(-0.6) = -0.6352... or x = 83.97..<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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