document.write( "Question 258157: Solve the equations by substitution.\r
\n" ); document.write( "\n" ); document.write( "8x = 2y + 5
\n" ); document.write( "3x = y + 7\r
\n" ); document.write( "\n" ); document.write( "x = ?
\n" ); document.write( "y = ?\r
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Algebra.Com's Answer #190053 by checkley77(12844)\"\" \"About 
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8x = 2y + 5
\n" ); document.write( "3x = y + 7 OR Y=3X-7
\n" ); document.write( "8X=2(3X-7)+5
\n" ); document.write( "8X=6X-14+5
\n" ); document.write( "8X-6X=-9
\n" ); document.write( "2X=-9
\n" ); document.write( "X=-9/2
\n" ); document.write( "X=-4.5 ANS.
\n" ); document.write( "8*-4.5=2Y+5
\n" ); document.write( "-36=2Y+5
\n" ); document.write( "2Y=-36-5
\n" ); document.write( "2Y=-41
\n" ); document.write( "Y=-41/2
\n" ); document.write( "Y=-20.5 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*-4.5=-20.5+7
\n" ); document.write( "-13.5=-13.5\r
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