document.write( "Question 258129: Need your help again. Question: A plane flies a distance of 2900 miles. With the tailwind, it averaged 600 mph. When the wind changed from a tailwind to a headwind, the speed dropped to 550 mph. Total trip time is 5 hours. Determine the length of time it flew at each speed.\r
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document.write( "My solution was: x/600 + 2900 - x/550 = 5, which didn't work. Thanks!! \n" );
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Algebra.Com's Answer #190001 by drk(1908) ![]() You can put this solution on YOUR website! This is an RTD problem. Here is a table based on the given information: \n" ); document.write( "PLANE . . . . .rate . . . . . . . . time . . . . . . . . . distance \n" ); document.write( "with . . . . . r+c = 600 . . . . . . Tw . . . . . . . . . . 600Tw \n" ); document.write( "against . . . . r-c = 550 . . . . . . Ta . . . . . . . . . . 550Ta \n" ); document.write( "total . . . . . . . . . . . . . . . . .5 . . . . . . . . . . 2900 \n" ); document.write( "we have two equations: \n" ); document.write( "(i) \n" ); document.write( "(ii) \n" ); document.write( "we simplify (ii) to be \n" ); document.write( "(iii) \n" ); document.write( "multiply (i) by -11 to get \n" ); document.write( "(iv) \n" ); document.write( "adding (iii) and (iv) we get \n" ); document.write( " \n" ); document.write( "or 3 hours flying with the wind. \n" ); document.write( "This means that \n" ); document.write( " \n" ); document.write( "or 2 hours flying against the wind. \n" ); document.write( " |