document.write( "Question 258129: Need your help again. Question: A plane flies a distance of 2900 miles. With the tailwind, it averaged 600 mph. When the wind changed from a tailwind to a headwind, the speed dropped to 550 mph. Total trip time is 5 hours. Determine the length of time it flew at each speed.\r
\n" ); document.write( "\n" ); document.write( "My solution was: x/600 + 2900 - x/550 = 5, which didn't work. Thanks!!
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Algebra.Com's Answer #190001 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
This is an RTD problem. Here is a table based on the given information:
\n" ); document.write( "PLANE . . . . .rate . . . . . . . . time . . . . . . . . . distance
\n" ); document.write( "with . . . . . r+c = 600 . . . . . . Tw . . . . . . . . . . 600Tw
\n" ); document.write( "against . . . . r-c = 550 . . . . . . Ta . . . . . . . . . . 550Ta
\n" ); document.write( "total . . . . . . . . . . . . . . . . .5 . . . . . . . . . . 2900
\n" ); document.write( "we have two equations:
\n" ); document.write( "(i) \"Tw+%2B+Ta+=+5\"
\n" ); document.write( "(ii) \"600Tw+%2B+550Ta+=+2900\"
\n" ); document.write( "we simplify (ii) to be
\n" ); document.write( "(iii) \"12Tw+%2B+11Ta+=+58\"
\n" ); document.write( "multiply (i) by -11 to get
\n" ); document.write( "(iv) \"-11Tw+-+11Ta+=+-55\"
\n" ); document.write( "adding (iii) and (iv) we get
\n" ); document.write( "\"Tw+=+3\"
\n" ); document.write( "or 3 hours flying with the wind.
\n" ); document.write( "This means that
\n" ); document.write( "\"Ta+=+2\"
\n" ); document.write( "or 2 hours flying against the wind.
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