document.write( "Question 4271: Find the equation of the axis of symmetry for the following parabola y = x^2 - 6x + 7 \n" ); document.write( "
Algebra.Com's Answer #1900 by rapaljer(4671)\"\" \"About 
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For a graph of a parabola that opens up or down in the form \r
\n" ); document.write( "\n" ); document.write( "\"y+=+ax%5E2+%2B+bx+%2B+c\"\r
\n" ); document.write( "\n" ); document.write( "the vertex and therefore the axis of symmetry is always at\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b%29%2F2a\". This formula comes from the quadratic formula!! \"x=%28-b%2B-sqrt+%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the axis of symmetry for
\n" ); document.write( "\"y+=+x%5E2+-+6x+%2B+7\" where a=1, b=-6, and c=7
\n" ); document.write( "is \"x=%28-%28-6%29%29%2F%282%281%29%29\" or x=3\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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