document.write( "Question 257969: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller part. What is the smaller part of the investment? \n" ); document.write( "
Algebra.Com's Answer #189999 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .06x=.05(10,000-x)+160 \n" ); document.write( ".06x=500-.05x+160 \n" ); document.write( ".06x+.05x=660 \n" ); document.write( ".11x=660 \n" ); document.write( "x=660/.11 \n" ); document.write( "x=$6,000 amount invested @ 6% \n" ); document.write( "10,000-6,000=$4,000 invested @5% \n" ); document.write( "Proof: \n" ); document.write( ".06*6,000=.05*4,000+160 \n" ); document.write( "360=200+160 \n" ); document.write( "360=360 \n" ); document.write( " |