document.write( "Question 258094: The perimeter of a rectangle is 54. If the length is three more than twice the width, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #189958 by checkley77(12844)\"\" \"About 
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L=2W+3
\n" ); document.write( "2L+2W=54
\n" ); document.write( "2(2W+3)+2W=54
\n" ); document.write( "4W+6+2W=54
\n" ); document.write( "6W=54-6
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 ANS.
\n" ); document.write( "L=2*8+3
\n" ); document.write( "L=16+3=19 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*19+2*8=54
\n" ); document.write( "38+16=54
\n" ); document.write( "54=54
\n" ); document.write( "
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