document.write( "Question 258094: The perimeter of a rectangle is 54. If the length is three more than twice the width, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #189958 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+3 \n" ); document.write( "2L+2W=54 \n" ); document.write( "2(2W+3)+2W=54 \n" ); document.write( "4W+6+2W=54 \n" ); document.write( "6W=54-6 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 ANS. \n" ); document.write( "L=2*8+3 \n" ); document.write( "L=16+3=19 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "2*19+2*8=54 \n" ); document.write( "38+16=54 \n" ); document.write( "54=54 \n" ); document.write( " |