document.write( "Question 258079: I have to solve this problem by substitution:\r
\n" ); document.write( "\n" ); document.write( "2x + y = 6\r
\n" ); document.write( "\n" ); document.write( "x= 3y + 10\r
\n" ); document.write( "\n" ); document.write( "I begin by using the 2(3y + 10)+ y = 6
\n" ); document.write( "Multiply: (6y + 20) + y = 6
\n" ); document.write( "add 6y + y to get 7y + 20= 6
\n" ); document.write( " -20= 6 -20
\n" ); document.write( " 7y = -14
\n" ); document.write( " 7ydivided by 7 = -14 divided by 7
\n" ); document.write( " y = -2\r
\n" ); document.write( "\n" ); document.write( "put the -2 for the y x = 3 (-2) + 10
\n" ); document.write( " x = -6 + 10
\n" ); document.write( " x = 4
\n" ); document.write( "so my answer would be\r
\n" ); document.write( "\n" ); document.write( "(4,-2)\r
\n" ); document.write( "\n" ); document.write( "My answer works out when I check my work. Please confirm that my work is correct.
\n" ); document.write( "
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Algebra.Com's Answer #189931 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
GOOD JOB! \n" ); document.write( "
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