document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257991>Question 257991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the interior angles of a triangle are 180 deg. If the measure of one angle is twice the measure of a second angle, and the measure of a third angle is 40 deg less than the second, find the measure of all three angles of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189926 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let first angle be 2y, then second angle is y and the third is y - 40.<BR>\n" );
document.write( "Sum is y + 2y + y - 40 = 180<BR>\n" );
document.write( "4y = 220<BR>\n" );
document.write( "y = 55<BR>\n" );
document.write( "So angles are 110, 55, 15 </SPAN>\n" );
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