document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258057>Question 258057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please answer this question.<BR>\n" );
document.write( "An object is launched upward at 45ft/Sec from a platform that is 40 feet high. What is the objects maximum height if the equation of the height(h) in terms of time (t) of the object is given by h(t) = -16t^2 + 45t + 40?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189907 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h = 16t^2 + 45t + 40<BR>\n" );
document.write( "dh/dt = 32t + 45. When dh/dt = 0, h is a stationary point<BR>\n" );
document.write( "this is at t = 45/32 = 1.406 seconds<BR>\n" );
document.write( "so h = 32 x(1.406^2 + 45x 1.406 + 40 = 63.25 + 63.27 + 40 = 166.52 feet  </SPAN>\n" );
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