document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258057>Question 258057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please answer this question.<BR>\n" );
document.write( "An object is launched upward at 45ft/Sec from a platform that is 40 feet high. What is the objects maximum height if the equation of the height(h) in terms of time (t) of the object is given by h(t) = -16t^2 + 45t + 40?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189905 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An object is launched upward at 45ft/Sec from a platform that is 40 feet high. What is the object's maximum height if the equation of the height(h) in terms of time (t) of the object is given by h(t) = -16t^2 + 45t + 40?<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "max occurs when x = -b/2a = -45/(2*-16) = 1.40625<BR>\n" );
document.write( "The max height is f(1.40625) = -16(-1.40625)^2 + 45(1.40625) + 40<BR>\n" );
document.write( "= 71.64 ft.<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );