document.write( "Question 4267: ALRIGHTY
\n" ); document.write( "THE MURRAYS HAVE INVESTED MONEY IN TWO ACCOUNTS. ONE PAYS 7% INTEREST AND THE OTHER PAYS 8.5% INTEREST. THEY INVESTED $1000 MORE AT 8.5% THAN THEY INVESTED AT 7%. IF THE TOTAL INTEREST EARNED IN ONE YEAR IS $395, HOW MUCH MONEY HAVE THEY INVESTED IN EACH ACCOUNT?\r
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Algebra.Com's Answer #1899 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = principle invested at 7% or .07
\n" ); document.write( " x+1000 = principle invested at 8.5% or .085\r
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\n" ); document.write( "\n" ); document.write( "Total interest for the year is the sum of the interest on each account, which is given by Principle * Rate for the year. \r
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\n" ); document.write( "\n" ); document.write( "The equation is:\r
\n" ); document.write( "\n" ); document.write( " .07(x) + .085(x+1000) = 395
\n" ); document.write( " .07x + .085x + 85 = 395
\n" ); document.write( " .155x + 85 = 395
\n" ); document.write( " .155x = 310\r
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\n" ); document.write( "\n" ); document.write( "Divide each side by .155, which gives you
\n" ); document.write( " \".155x%2F.155+=+310%2F.155\"
\n" ); document.write( "So, x = 310/.155 = 310000/155 = $2000\r
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\n" ); document.write( "\n" ); document.write( "x = $2000 @ 7%
\n" ); document.write( "x+1000 = $3000 @8.5%\r
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\n" ); document.write( "\n" ); document.write( "Check by adding up the interest:
\n" ); document.write( " .07(2000) + .085(3000)
\n" ); document.write( " 140 + 170 = $310\r
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\n" ); document.write( "\n" ); document.write( "I hope that helps\r
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\n" ); document.write( "\n" ); document.write( "R^2 from SCC\r
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\n" ); document.write( "\n" ); document.write( "P.S. Are you from the church school that posed problem #4130 and later commented in #4162??
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