document.write( "Question 257925: Three friends-whose walking rates are 1 ft./sec., 3 ft./sec., and 6 ft./sec.- start out together walking in the same direction around a circular track that is 300 feet in circumference. After how many minutes are the three of them together again?
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Algebra.Com's Answer #189871 by ankor@dixie-net.com(22740)\"\" \"About 
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Three friends-whose walking rates are 1 ft./sec., 3 ft./sec., and 6 ft./sec.- start out together walking in the same direction around a circular track that is 300 feet in circumference.
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\n" ); document.write( "find a multiple of the track dist using the fast guy: 6 ft/sec
\n" ); document.write( "6 * 300 = 1800 ft
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\n" ); document.write( "Fast guy: 300 sec or 5 min to complete(6 laps)
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\n" ); document.write( "2nd fast guy: 300 sec * 3 = 900 ft in 5 min (3laps)
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\n" ); document.write( "slow guy 300 sec * 1 = 300 ft in 5 min, (1lap)
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\n" ); document.write( "Should all be starting a new lap in 5 min
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