document.write( "Question 257925: Three friends-whose walking rates are 1 ft./sec., 3 ft./sec., and 6 ft./sec.- start out together walking in the same direction around a circular track that is 300 feet in circumference. After how many minutes are the three of them together again?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #189871 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Three friends-whose walking rates are 1 ft./sec., 3 ft./sec., and 6 ft./sec.- start out together walking in the same direction around a circular track that is 300 feet in circumference. \n" ); document.write( " After how many minutes are the three of them together again? \n" ); document.write( ": \n" ); document.write( "find a multiple of the track dist using the fast guy: 6 ft/sec \n" ); document.write( "6 * 300 = 1800 ft \n" ); document.write( ": \n" ); document.write( "Fast guy: 300 sec or 5 min to complete(6 laps) \n" ); document.write( ": \n" ); document.write( "2nd fast guy: 300 sec * 3 = 900 ft in 5 min (3laps) \n" ); document.write( ": \n" ); document.write( "slow guy 300 sec * 1 = 300 ft in 5 min, (1lap) \n" ); document.write( ": \n" ); document.write( "Should all be starting a new lap in 5 min \n" ); document.write( " |