document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258020>Question 258020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of the line that passes through (-3,2) and is parallel to the line x-y=7.\r<BR>\n" );
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document.write( "I dont understand how to do this problem. Or even start it for that matter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189868 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The line x - y = 7 can be rewritten as y = x - 7<BR>\n" );
document.write( "The gradient of the line is 1, because each increase of 1 in the value of x produces an increase in y of 1 as well.\r<BR>\n" );
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document.write( "Any line parallel (||) will also have a gradient of 1, so all lines || to<BR>\n" );
document.write( " y = x -7 will be of the form y = x + c where c is a constant<BR>\n" );
document.write( "The line we are interested in goes through (-3,2) so we put these numbers into the equation so 2 = -3 + c<BR>\n" );
document.write( "so c = 5<BR>\n" );
document.write( "The equation is y = x + 5 </SPAN>\n" );
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