document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258005>Question 258005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Running at an average rate of 6 meters per second, a sprinter ran to the end of the track. The sprinter then jogged back to the starting point at an average rate of 3 meters per second. The total time for the sprint and the jog back was 2 minutes and 40 seconds. Find the length of the track. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189857 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 minutes 40 seconds=160 seconds\r<BR>\n" );
document.write( "\n" );
document.write( "6x=3(160-x)\r<BR>\n" );
document.write( "\n" );
document.write( "x=160/3<BR>\n" );
document.write( "6*160/3=2*160=320 meters long<BR>\n" );
document.write( "check<BR>\n" );
document.write( "6*160/3+3*(160-160/3)=640\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );