document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257899>Question 257899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of a bicycle shop took inventory of his bicycles and tricycles. He counted 153 wheels and 136 pedals. How many bicycles and tricycles did he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189829 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 136/2= 68 pedal vehicles<BR>\n" );
document.write( "153-136=number of wheels -minus number of pedals = 17 tricycles<BR>\n" );
document.write( "68-17=51 bicycles<BR>\n" );
document.write( "check<BR>\n" );
document.write( "2b+3t=w<BR>\n" );
document.write( "2*51+3*17=153<BR>\n" );
document.write( "102+51=153<BR>\n" );
document.write( "ok<BR>\n" );
document.write( "check<BR>\n" );
document.write( "68*2=136<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );