document.write( "Question 257942: Solve for x.\r
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Algebra.Com's Answer #189800 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Solve for x.
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document.write( "Get all the terms that have x in them on one side and\r\n" );
document.write( "all the terms that don't have x in them on the other side:\r\n" );
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document.write( "\"abx-ax=b-1\"\r\n" );
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document.write( "Factor out x, the letter you are solving for:\r\n" );
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document.write( "\"x%28ab-a%29=b-1\"\r\n" );
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document.write( "Divide both sides by \"%28ab-a%29\"\r\n" );
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document.write( "\"x%28ab-a%29%2F%28ab-a%29=%28b-1%29%2F%28ab-a%29\"\r\n" );
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document.write( "\"x%28cross%28ab-a%29%29%2F%28cross%28ab-a%29%29=%28b-1%29%2F%28ab-a%29\"\r\n" );
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document.write( "\"x=%28b-1%29%2F%28ab-a%29\"\r\n" );
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document.write( "But you aren't finished yet because you can\r\n" );
document.write( "factor a out of the denominator on the right:\r\n" );
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document.write( "\"x=%28b-1%29%2F%28a%28b-1%29%29\"\r\n" );
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document.write( "Then cancel:\r\n" );
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document.write( "\"x=%28cross%28b-1%29%29%2F%28a%28cross%28b-1%29%29%29\"\r\n" );
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document.write( "\"x=1%2Fa\"  \r\n" );
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document.write( "Be sure you realize that you don't get \"a\"\r\n" );
document.write( " because the \"a\" was in a denominator and\r\n" );
document.write( "you must keep it in the denominator after canceling\r\n" );
document.write( "out the \"%28b-1%29\"'s by putting a 1 over it.\r\n" );
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document.write( "Edwin
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