document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257945>Question 257945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary.If one angle measures 45 degrees less than twice the measure of its supplement, find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189796 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call first angle y, then other angle is (180 - y)<BR>\n" );
document.write( "y + 45 = 2(180 - y)<BR>\n" );
document.write( "y + 45 = 360 - 2y<BR>\n" );
document.write( "3y = 315<BR>\n" );
document.write( "y = 105<BR>\n" );
document.write( "So angles are 105 and 75<BR>\n" );
document.write( "Check : y + 45 = 150 which is twice 75 </SPAN>\n" );
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