document.write( "Question 257819: A balanced coin is tossed 8 times. What is the probability of getting exactly 2 heads given that there were at least 2 heads in the 8 tosses? \n" ); document.write( "
Algebra.Com's Answer #189725 by edjones(8007)\"\" \"About 
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Let h=.5 and t=.5, probability of heads or tails.
\n" ); document.write( "We need to find a number in the expansion of the binomial (h+t)^8
\n" ); document.write( "We are looking for h^2t^6
\n" ); document.write( "The coefficient is nCr=8C2=28 Combination
\n" ); document.write( "28h^2t^6=28*.25*.0156=.1094 prob of exactly 2 heads.
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\n" ); document.write( "1-t^8-8t^7h=1-.0039-(8*.0078*.5)
\n" ); document.write( "=1-.0039-.03125
\n" ); document.write( "=.9649 prob of at least 2 heads.
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\n" ); document.write( ".1094/.9649=.1134 probability of getting exactly 2 heads given that there were at least 2 heads in the 8 tosses.
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