document.write( "Question 257662: the length of a rectangular picture is 4 less than twice its width. it is placed in a wooden frame with a unifiorm width of 2 inches. The perimeter of the picture frame is 102 inches. what is the dimension of the rectangular picture? \n" ); document.write( "
Algebra.Com's Answer #189724 by ankor@dixie-net.com(22740)\"\" \"About 
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the length of a rectangular picture is 4 less than twice its width.
\n" ); document.write( " it is placed in a wooden frame with a uniform width of 2 inches.
\n" ); document.write( " The perimeter of the picture frame is 102 inches.
\n" ); document.write( " what is the dimension of the rectangular picture?
\n" ); document.write( ":
\n" ); document.write( "Let x = the width
\n" ); document.write( "it states:\"the length of a rectangular picture is 4 less than twice its width.\"
\n" ); document.write( "Therefore:
\n" ); document.write( "L = (2x - 4)
\n" ); document.write( ":
\n" ); document.write( "Perimeter
\n" ); document.write( "2L + 2x = 102
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "L + x = 51
\n" ); document.write( "Replace L with (2x-4), find x:
\n" ); document.write( "2x - 4 + x = 51
\n" ); document.write( "3x = 51 + 4
\n" ); document.write( "3x = 55
\n" ); document.write( "x = 55/3
\n" ); document.write( "x = 18\"1%2F3\" inches is the frame width
\n" ); document.write( "then
\n" ); document.write( "L = 2(18\"1%2F3\") - 4
\n" ); document.write( "L = 36\"2%2F3\" - 4
\n" ); document.write( ":
\n" ); document.write( "L = 32\"2%2F3\" inches is the frame length
\n" ); document.write( ":
\n" ); document.write( "A picture frame with 2 inches width all around, subtract 4 inches
\n" ); document.write( "therefore
\n" ); document.write( "18\"1%2F3\" - 4 = 14\"1%2F3\" picture width
\n" ); document.write( ":
\n" ); document.write( "32\"2%2F3\" - 4 = 28\"2%2F3\" picture length
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Note to students response.
\n" ); document.write( " Actually I think you have to subtract 16\" from the frame perimeter to get the picture perimeter.
\n" ); document.write( "Then the picture length and width will agree. (86\")\r
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