document.write( "Question 257815: The length of a rectangle is 2 ft more than four times the width. Express as an interger the maximum width of the rectangle when the perimeter is less than 34 ft ? \n" ); document.write( "
Algebra.Com's Answer #189707 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Let length = L and width = W. \n" ); document.write( "from the given information, we get \n" ); document.write( " L = 4W + 2 \n" ); document.write( "P = 2L + 2W \n" ); document.write( "34 > 2(4W+2) + 2W \n" ); document.write( "34 > 10W + 4 \n" ); document.write( "30 > 10W \n" ); document.write( "3 > W \n" ); document.write( "The maximum width is 2. \n" ); document.write( "If W = 2 \n" ); document.write( "L = 10 \n" ); document.write( "P = 24 < 34 \n" ); document.write( "-- \n" ); document.write( "If W = 3 \n" ); document.write( "L = 14 \n" ); document.write( "P = 34 this is NOT LESS than 34. \n" ); document.write( " |