document.write( "Question 257815: The length of a rectangle is 2 ft more than four times the width. Express as an interger the maximum width of the rectangle when the perimeter is less than 34 ft ? \n" ); document.write( "
Algebra.Com's Answer #189707 by drk(1908)\"\" \"About 
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Let length = L and width = W.
\n" ); document.write( "from the given information, we get
\n" ); document.write( " L = 4W + 2
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "34 > 2(4W+2) + 2W
\n" ); document.write( "34 > 10W + 4
\n" ); document.write( "30 > 10W
\n" ); document.write( "3 > W
\n" ); document.write( "The maximum width is 2.
\n" ); document.write( "If W = 2
\n" ); document.write( "L = 10
\n" ); document.write( "P = 24 < 34
\n" ); document.write( "--
\n" ); document.write( "If W = 3
\n" ); document.write( "L = 14
\n" ); document.write( "P = 34 this is NOT LESS than 34.
\n" ); document.write( "
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