document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257810>Question 257810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Number 1\r<BR>\n" );
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document.write( "A chemist is making a solution that is to be 55% chlorine. He has one solution that is 40% chlorine and another that is 65% chlorine. He wants 100 liters of the final solution. How much of each should he mix?\r<BR>\n" );
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document.write( "a. Choose a variable to represent the amount of the first solution. Then find the amount of the second solution to be added to make 100 liters. Now figure out how much chlorine is in each solution.\r<BR>\n" );
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document.write( "b. Write the equation.\r<BR>\n" );
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document.write( "c. Solve the equation.\r<BR>\n" );
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document.write( "a. Use x for the amount of the first solution.<BR>\n" );
document.write( "Use (100 - x) for the amount of the second <BR>\n" );
document.write( "solution. This is because when the two are <BR>\n" );
document.write( "added together you want 100 liters of final<BR>\n" );
document.write( "solution. For the amount of chlorine you <BR>\n" );
document.write( "multiply the proper percentage and the <BR>\n" );
document.write( "amount of solution. For the first it is (.40x),<BR>\n" );
document.write( "and for the second it is .65(100-x) or <BR>\n" );
document.write( "(65 - .65x). You want 100 liters of final <BR>\n" );
document.write( "solution at 55% chlorine, so that means <BR>\n" );
document.write( ".55(100) or 55. \r<BR>\n" );
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document.write( "b. Add the first two solutions, and write the<BR>\n" );
document.write( "equation (simplified): .40x + 65 - .65x = 55 \r<BR>\n" );
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document.write( "c. Solve<BR>\n" );
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document.write( "Amount Solution<BR>\n" );
document.write( "% CI<BR>\n" );
document.write( "Amount Chlorine<BR>\n" );
document.write( "X<BR>\n" );
document.write( "40%<BR>\n" );
document.write( ".40X<BR>\n" );
document.write( "100-X<BR>\n" );
document.write( "65%<BR>\n" );
document.write( ".65(100-X)<BR>\n" );
document.write( "100<BR>\n" );
document.write( "55%<BR>\n" );
document.write( ".55(100)<BR>\n" );
document.write( "The equation comes from the last column.<BR>\n" );
document.write( "Sol 1 + Sol 2 = Final solution\r<BR>\n" );
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document.write( ".40x + .65(100-x) = .55(100) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189698 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist is making a solution that is to be 55% chlorine. He has one solution that is 40% chlorine and another that is 65% chlorine. He wants 100 liters of the final solution. How much of each should he mix? <BR>\n" );
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document.write( "It's not that complicated.<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "chlorine + chlorine = chlorine<BR>\n" );
document.write( "0.40x + 0.65(100-x) = 0.55*100<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40x + 65*100 - 65x = 55*100<BR>\n" );
document.write( "-15x = -10*100<BR>\n" );
document.write( "x = 66 2/3 liters (amt. of 40% solution needed in the mixture)<BR>\n" );
document.write( "100 - x = 33 1/3 liters (amt. of 65% solution needed in the mixture<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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