document.write( "Question 257803: A company makes 3 types of cable. Cable A requires 3 black wires, 3 white wires, and 2 red wires. Cable B requires 1 black, 2 white, and 1 red. Cable C requires 2 black, 1 white, and 2 red. If 95 black wires, 100 white wires, and 80 red wires were used, then how many of each cable were made? \n" ); document.write( "
Algebra.Com's Answer #189673 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Here we have a 3x3 system. \n" ); document.write( "Let the cables be A, B, and C. \n" ); document.write( "(i) 3A + 1B + 2C = 95 \n" ); document.write( "(ii) 3A + 2B + 1C = 100 \n" ); document.write( "(iii) 2A + 1B + 2C = 80 \n" ); document.write( "-- \n" ); document.write( "Lets eliminate the B's. Take (ii) - 2*(i) to get \n" ); document.write( "(iv) -3A -3C = -90 \n" ); document.write( "lets eliminate the B's. take (ii) - 2*(iii) to get \n" ); document.write( "(v) -1A -3C = -60 \n" ); document.write( "-- \n" ); document.write( "To eliminate C's, take (v) - (iv) to get \n" ); document.write( "(vi) 2A = 30 so \n" ); document.write( "A = 15 cables \n" ); document.write( "C = 15 cables \n" ); document.write( "B = 20 cables \n" ); document.write( " |