document.write( "Question 257803: A company makes 3 types of cable. Cable A requires 3 black wires, 3 white wires, and 2 red wires. Cable B requires 1 black, 2 white, and 1 red. Cable C requires 2 black, 1 white, and 2 red. If 95 black wires, 100 white wires, and 80 red wires were used, then how many of each cable were made? \n" ); document.write( "
Algebra.Com's Answer #189673 by drk(1908)\"\" \"About 
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Here we have a 3x3 system.
\n" ); document.write( "Let the cables be A, B, and C.
\n" ); document.write( "(i) 3A + 1B + 2C = 95
\n" ); document.write( "(ii) 3A + 2B + 1C = 100
\n" ); document.write( "(iii) 2A + 1B + 2C = 80
\n" ); document.write( "--
\n" ); document.write( "Lets eliminate the B's. Take (ii) - 2*(i) to get
\n" ); document.write( "(iv) -3A -3C = -90
\n" ); document.write( "lets eliminate the B's. take (ii) - 2*(iii) to get
\n" ); document.write( "(v) -1A -3C = -60
\n" ); document.write( "--
\n" ); document.write( "To eliminate C's, take (v) - (iv) to get
\n" ); document.write( "(vi) 2A = 30 so
\n" ); document.write( "A = 15 cables
\n" ); document.write( "C = 15 cables
\n" ); document.write( "B = 20 cables
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