document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257685>Question 257685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189661 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jack usually mows his lawn in 7 hours. Marilyn can mow the same yard in 5 hours. How much time would it take for them to mow together?\r<BR>\n" );
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document.write( "Jack's mowing rate is 1/7 lawns per hour. Marilyn's rate is 1/5 lawns per hour.\r<BR>\n" );
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document.write( "Their combined rate is 1/7 + 1/5.\r<BR>\n" );
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document.write( "Let t be the time it takes for the two of them to mow 1 lawn together. Then:\r<BR>\n" );
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document.write( "(1/7 + 1/5)*t = 1<BR>\n" );
document.write( "12/35 * t = 1<BR>\n" );
document.write( "t = 35/12 hours  </SPAN>\n" );
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