document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257708>Question 257708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have three problems that are factoring\r<BR>\n" );
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document.write( "Factoring - Finding GCF<BR>\n" );
document.write( "            Reverse FOIL (Quadratic - 2 binomials)<BR>\n" );
document.write( "8y^3 + 2y - 4y^2<BR>\n" );
document.write( "for this one:  I got the answer 2y (4y^2+1-2y) please tell me if this is right.\r<BR>\n" );
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document.write( "x^2 + 5x +6\r<BR>\n" );
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document.write( "for this one:  I got the answer (x-1)(x+5)  I'm not sure about this one.\r<BR>\n" );
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document.write( "y^2 - 4y -12\r<BR>\n" );
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document.write( "(y      )(y       ) This is as far as I got on this one.  Please help.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189586 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's do the last one first<BR>\n" );
document.write( "we want factors of 12 that add up to 4 or have a difference of 4<BR>\n" );
document.write( "since both -4y qnd -12 are negative the difference has to be 4<BR>\n" );
document.write( "If they were both negative then the 12 would be +12<BR>\n" );
document.write( "1,12<BR>\n" );
document.write( "6,2<BR>\n" );
document.write( "3,4\r<BR>\n" );
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document.write( "6 and 2<BR>\n" );
document.write( "so the 6 is - and the 2 is plus<BR>\n" );
document.write( "(x-6)(x+2)\r<BR>\n" );
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document.write( "(y-6) (y+2)\r<BR>\n" );
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document.write( "the first one is right<BR>\n" );
document.write( "You aren't even close on the second one<BR>\n" );
document.write( "-1*5 doesn't=6 <BR>\n" );
document.write( "we need factors of 6 that add up to 5<BR>\n" );
document.write( "both positive\r<BR>\n" );
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document.write( "BTW the website rules say<BR>\n" );
document.write( " one problem per submission - one rule broken<BR>\n" );
document.write( "no similar problems- two rules broken<BR>\n" );
document.write( "also a limit of 4 submission/problems daily<BR>\n" );
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