document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32459>Question 32459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ((( cindy has $6.05 in quarters and nickels.  How many of each coin does she have if there are 53 coins in all.)))) Can you please help me set up this problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18956 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=53 AND 5X+25Y=605 X=53-Y SUBSTITUTING IN THE SECOND EQUATION WE GET\r<BR>\n" );
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document.write( "5(53-Y)+25Y=605 OR 265-5Y+25Y=605 OR 20Y=340 OR Y=17 THEREFORE X=53-17 OR X=36\r<BR>\n" );
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document.write( "PROOF 5*36+17*25=605 OR 180+425=605 OR 605=605 </SPAN>\n" );
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