document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32461>Question 32461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (((The perimeter of a rectangle is 1100ft find the dimesnions so that the enclosed area will be 60,000 square ft))))  please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18952 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+2Y=1100 & X*Y=60000 THEREFORE 2X=1100-2Y OR X=(1100-2Y)/2 OR X=550-Y<BR>\n" );
document.write( "SUBSTITUTING IN EQUATION 2 WE GET (550-Y)Y=60000 OR 550Y-Y~2=60000 OR <BR>\n" );
document.write( "-Y~2+550-60000=0 OR Y~2-550+60000 OR (Y-400)(Y-150)=0 OR Y=400 THEN <BR>\n" );
document.write( "X=60000/400 OR X=150 OR Y=150 THEN X=60000/150 OR X=400<BR>\n" );
document.write( "PROOF 2*400+2*150=1100 OR 800+300=1100 <BR>\n" );
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