document.write( "Question 32461: (((The perimeter of a rectangle is 1100ft find the dimesnions so that the enclosed area will be 60,000 square ft)))) please help \n" ); document.write( "

Algebra.Com's Answer #18951 by Paul(988) $\"\"$ $\"About$

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THe formula for the perimeter is:
\n" ); document.write( "2(l+w)=P
\n" ); document.write( "In this case P = 1100 and length and width are unknown.
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2l+2w=1100
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document.write( "Solve for length:
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document.write( "l=550-w (subsitution)
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document.write( "The Area in this case is A=60000
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document.write( "lw=60000
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document.write( "Subsitute for l
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document.write( "(550-w)(w)=60000
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document.write( "Factor: (w-150) or (w-400)
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document.write( "Remvoe the 150 x=400
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document.write( "l=550-400
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document.write( "l=150
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document.write( "Hence, the width is 150ft and the length is 400ft.
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document.write( "Paul.
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