document.write( "Question 257589: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the object is airborne. A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter \n" ); document.write( "
Algebra.Com's Answer #189502 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the object is airborne. \n" ); document.write( "------------------------------------------ \n" ); document.write( "A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter \n" ); document.write( "-------------------- \n" ); document.write( "a(t) = h + vt - 9.8t^2 \n" ); document.write( "a(3) = 164 + 36(3) - 9(3)^2 \n" ); document.write( "a(3) = 164 + 108 - 81 \n" ); document.write( "a(3) = 191 meters \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |