document.write( "Question 257493: I have a final today and there will be similar questions as this one. Can someone please help me understand this problem.\r
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document.write( "The fracture strength of a certain type of manufactured glass is normally distributed with a mean of 579 MPa with a standard deviation of 14 MPa. (a) What is the probability that a randomly chosen sample of glass will break at less than 579 MPa? (b) More than 590 MPa? (c) Less than 600 MPa?
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Algebra.Com's Answer #189418 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The fracture strength of a certain type of manufactured glass is normally distributed with a mean of 579 MPa with a standard deviation of 14 MPa. (a) What is the probability that a randomly chosen sample of glass will break at less than 579 MPa? (b) More than 590 MPa? (c) Less than 600 MPa? \n" ); document.write( "--------------------- \n" ); document.write( "You have to convert to z-scores. \n" ); document.write( "-------------- \n" ); document.write( "(a) What is the probability that a randomly chosen sample of glass will break at less than 579 MPa? \n" ); document.write( "z(579)= (579-579)/14 = 0 \n" ); document.write( "P(x < 579) = P(z < 0) = 0.5000 \n" ); document.write( "----------------------------------- \n" ); document.write( "(b) More than 590 MPa? \n" ); document.write( "z(590) = (590-579)/14 = 11/14= 0.7857... \n" ); document.write( "P(x > 590) = P(z > 0.7857..) = 0.2160... \n" ); document.write( "----------------------------------- \n" ); document.write( "(c) Less than 600 MPa? \n" ); document.write( "z(600) = (600-579)/14 = 21/14 = 3/2 \n" ); document.write( "P(x < 600) = P(z< 3/2) = 0.9332 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |