document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257489>Question 257489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you have 80 feet of fencing to enclose a rectangular region. what is the maximum area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189413 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is<BR>\n" );
document.write( "P = 2L + 2W or<BR>\n" );
document.write( "80 = 2L + 2W<BR>\n" );
document.write( "dividing by 2 we get<BR>\n" );
document.write( "(i) 40 = L + W<BR>\n" );
document.write( "THe area is <BR>\n" );
document.write( "(ii) A = LW<BR>\n" );
document.write( "solving (i) for L, we get<BR>\n" );
document.write( " (iii) L = 40-W<BR>\n" );
document.write( "substituting that in (ii), we get<BR>\n" );
document.write( "(iv) A = (40-W)(W)<BR>\n" );
document.write( "using completing the square, we get<BR>\n" );
document.write( "A = -(W-20)^2 + 400<BR>\n" );
document.write( "So, when W = 20, the max area is 400. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );